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2x^2+33x-7.5=0
a = 2; b = 33; c = -7.5;
Δ = b2-4ac
Δ = 332-4·2·(-7.5)
Δ = 1149
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-\sqrt{1149}}{2*2}=\frac{-33-\sqrt{1149}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+\sqrt{1149}}{2*2}=\frac{-33+\sqrt{1149}}{4} $
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